Will someone
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JDP Random then F cuz you got the wrong answer
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Plus the wrong process
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.
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Nah that could be still interpreted as a 59%, Letβs say 0 instead
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This aint fair at all
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JDP Random shouldnβt have cheated π
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@I_LΓΈve_ZΓΈf for k=1
x=cube root of A; y=cube root of B; z=cube root of C
where A+B+C=k
A,B,C can be any numbers, for k=1 for example A=0,25; B=0,4; C=0,35crX^3+crY^3+crZ^3=k
cr(0,25)^3+cr(0,4)^3+cr(0,35)^3=1
0,25+0,4+0,35=1
1=1For any other k, multiply both sides of that equation by k
k(cr(0,25)^3+cr(0,4)^3+cr(0,35)^3)=k*1
0,25k+0,4k+0,35k=k
k=keat shit, the amount of solutions is infinite considering x,y,z can be any number with any amount of numbers after decimal point
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@MGC 42
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JDP Random Photoshop
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Fake, stop forging legal documents
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πΉ
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bro
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JDP Random :)
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@I_LΓΈve_ZΓΈf mfw i spent 10 minutes writing a solution just to get hit by a fucking adam douglas reference
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@MGC ok
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Right this teacher must be fired!
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poor you
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JDP Random do it right π€·
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